XPO can’t limbo on IOW

I wonder if these drivers who hit bridges are going farther afield ( I o W ) as I can’t remember the last time I saw a report of chaos after a bridge strike in Grantham , mrs hasn’t mention anything lately
They do seem to be carrying on as before on a1 with crash after crash , see pics this week of accident between 2 foreigners where hfs went through hedge , across field & into another hedge , to be fair looking at accident looked like other lorry caused accident by just driving straight out lay-by onto a1

Stephenjp:
Doesn’t look like an XPO unit, the trailer definitely is, I think that’s probably a sub contractor…

If its a local should know better…

That’s going to be another brief to read and sign…lol

That’s an XPO unit on the British Gypsum contract.They have Scania and Volvo units on that contract

Roymondo:
Force = mass x ACCELERATION (not speed). You need to establish the time taken for the lorry and load to decelerate to zero and from that calculate its acceleration in metres per second per second.

I’d be happy to read your calculations to show what’s wrong with my calculation, but you have forgotten to include them, though TBH I don’t think TN is the place to be using the calculations found at lambdageeks.com/how-to-find-net … -velocity/

As per Newton’s second law,
But Momentum P = mv,
Fnet =(mv-mv0)/(t-t0)
Since mass m does not change when net force acts,
Fnet =m*[(v-v0)/(t-t0)]
An object’s velocity change (v=v0) per unit time change (t-t0) is an object’s acceleration ‘a’ due to net force.
a=(v-v0)/(t-t0)=Δv/Δt
Hence, Fnet = ma …………………. (*)

Besides which, it would appear to make little difference, here’s a more accessible view of the topic according to calculatorsoup.com/calculat … /force.php

Force Equation F=ma
Newton’s second law states that force is proportional to what is required for an object of constant mass to change its velocity. This is equal to that object’s mass multiplied by its acceleration. We use Newtons, kilograms, and meters per second squared as our default units, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour per second, millimeters per second2, etc.) could certainly be used as well - the calculation is the same regardless.

WheelsofCardiff:

Stephenjp:
Doesn’t look like an XPO unit, the trailer definitely is, I think that’s probably a sub contractor…

If its a local should know better…

That’s going to be another brief to read and sign…lol

That’s an XPO unit on the British Gypsum contract.They have Scania and Volvo units on that contract

Out of Robertsbridge it is Jempsons.

Could be an XPO tramper though.

Either way they have f’d it. The BG trailers are lower than the XPO at 14’ 7 with the scania midlift up. So they can’t even go with the excuse they thought it was a BG trailer.

I think those xpo are 14"11

Sent from my SM-G998B using Tapatalk

Zac_A:

Roymondo:
Force = mass x ACCELERATION (not speed). You need to establish the time taken for the lorry and load to decelerate to zero and from that calculate its acceleration in metres per second per second.

I’d be happy to read your calculations to show what’s wrong with my calculation, but you have forgotten to include them, though TBH I don’t think TN is the place to be using the calculations found at lambdageeks.com/how-to-find-net … -velocity/

As per Newton’s second law,
But Momentum P = mv,
Fnet =(mv-mv0)/(t-t0)
Since mass m does not change when net force acts,
Fnet =m*[(v-v0)/(t-t0)]
An object’s velocity change (v=v0) per unit time change (t-t0) is an object’s acceleration ‘a’ due to net force.
a=(v-v0)/(t-t0)=Δv/Δt
Hence, Fnet = ma …………………. (*)

Besides which, it would appear to make little difference, here’s a more accessible view of the topic according to calculatorsoup.com/calculat … /force.php

Force Equation F=ma
Newton’s second law states that force is proportional to what is required for an object of constant mass to change its velocity. This is equal to that object’s mass multiplied by its acceleration. We use Newtons, kilograms, and meters per second squared as our default units, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour per second, millimeters per second2, etc.) could certainly be used as well - the calculation is the same regardless.

The heavy type regarding the different units seems an unnecessary distraction.
Any units can be used, but the UK uses SI units as standard. (Except in Carryfasts and Ress-Moggs imaginations)
And although acceleration is often written as (Bloody keyboard!) m/s2, m·s−2 or ms−2, {\displaystyle {\tfrac {\operatorname {m} }{\operatorname {s} ^{2}}}}{\displaystyle {\tfrac {\operatorname {m} }{\operatorname {s} ^{2}}}}
I`m with Roymondo however, metres per second per second.

Looking at the picture and making shed loads of guesses and approximations.
10m/sec initial velocity? (Between 20 and 25mph.)
Stopped in a couple of metres? (Looking at picture)
So average speed 5m/s, so took, 0.4sec to stop? (assuming linear acceleration)
So -25m/s/s. About two a half g…is that reasonable?
Assuming 30t gross.
Putting that in the f=ma formula:
30,000 x 25 = 750,000 or about-ish-sort of 750ton force.

Open to correction on method and numbers.

It’s too late on a Sunday evening for more maths (for me at least) so I’ll happily accept your calculation, approximately three times more force than my example calculation, even worse for the bridge.

Regardless of where the true figure lies, some things are certain: those in charge were entirely right to stop trains running, the driver will be facing a driver conduct hearing and the operator a public inquiry.

It’s too late on a Sunday evening for more maths (for me at least) so I’ll happily accept your calculation, approximately three times more force than my example calculation, even worse for the bridge.

Regardless of where the true figure lies, some things are certain: those in charge were entirely right to stop trains running, the driver will be facing a driver conduct hearing and the operator a public inquiry.

Zac_A:
It’s too late on a Sunday evening for more maths (for me at least) so I’ll happily accept your calculation, approximately three times more force than my example calculation, even worse for the bridge.

Regardless of where the true figure lies, some things are certain: those in charge were entirely right to stop trains running, the driver will be facing a driver conduct hearing and the operator a public inquiry.

Same order of magnitude?..good enough innit.
And we do of course agree, inspect it, don`t chance it.