Sorry for resurrecting this thread, but I didn’t have anything better to do at the moment

Carryfast:
… Anyway long story short.Having more driven axles reduces the amount of force required to be applied at each driving wheel to overcome the inertia of the gross weight of a rigid,the combination weight of an artic,or the train weight of a drawbar outfit.Therefore less downforce on those drive wheels/axles is required for the required grip and traction co eficcient.What that means in the real world is that if you compare trucks of whatever comparable weight,in bad traction conditions,regardless of wether it’s grass/mud,snow/ice it’s the thing with more driven wheels which has the advantage. …
You almost got it right, but you left some important pieces out of equation.
What I agree with is that more drive axles reduces amount of force transferred by wheels to overcome the inertia.
What you didn’t take into account, or you didn’t mention, is you have to use cross and difflocks if you want to sum the forces affecting at each driving wheel. Of course, traction coefficient can be high enough that you don’t get any wheel spin at the first place, but it isn’t a situation we’re interested about. Lets again throw some numbers so the principle gets somewhat easier to understand. Lets stay you need 90 units of force to overcome inertia of your vehicle. Then lets use same legal setup I used in my previous post where I showed how 4x2 can transfer 47% more and 6x2 tag axle unit 100% more force to a solid surface than 6x4 unit before wheel spin occurs.
Lets say you can get 100 units of forward force per driving wheel on a 6x4 unit, which means 147 units of forward force per 4x2 unit driving wheel and 200 units for 6x2. If your throttle goes deep enough it’ll shoot power output of the engine over the limit allowed by traction coefficient between tyres and surface. This gives you wheel spin, which effectively cuts forward force by huge amount (no TC is assumed). For a 6x4 your margin between wheel spin and getting moving is 100-90=10 units of force. For 4x2 the marginal is 147-90=57 units of force and for 6x2 its 200-90=110 units of force. If you have clutch, lifting it up is likely to create a sudden rise in power transmitted to drivetrain which generates impulse type raise in the force which tyre should transfer. If amount of the force needed to overcome inertia and the amount of force tyre can transfer are close enough, this impulse is likely enough to invoke wheel spin.
When you engage diff or crosslock on 6x4 you have margin of 2100-90=110 units of force before you get wheel spin which will cut off your forward driving force. This is as much as you get from 6x2 out of the box. When you engage diff and crosslocks on 6x4 you have margin of 4100-90=310 units of force before you get wheel spin that stops you. Surprisingly, from 6x2 unit you get 2*200-90=310 units of force, which is same amount you get from your 6x4 unit. Differences which matter are that you have to engage some locks on a 6x4 before it matches traction give by 6x2. This requires you either to stop down or risk a breaking down your differentials on a long run when you lock them repeatedly while moving.
What I didn’t take into account is increased drag of the 6x4 (extra axle). I also didn’t take the increase in the surface pressure between tyre and surface into account with 4x2 and 6x2. This also has an (increasing) effect on the traction coefficient. Less surface supporting the same weight allows tyres to touch surface better than if you distribute the weight on a larger surface (think about hydroplaning or compare rally car tyres on a winter rallies to tyres used on an asphalt rallies).
Carryfast:
… ice is ice and snow is snow wether it’s 20 below or just 2 degrees below freezing. …
Actually it’s not. I’ll leave that to you as a homework to go out and check it by yourself how much more grip you have on ice and snow when it’s -20C compared to -2C.